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| Hi, kcat = Vmax/Km, where Vmax could be expressed in mnol/(mg min) and Km in uM, so kcat is expressed in min-1 one good book explaining all this is Enzyme Kinetics: Behavior and Analysis of Rapid Equilibrium and Steady-State Enzyme Systems (Wiley Classics Library)by Irwin H. Segel (Author) Best Regards Analía Good evening From your data you can first calcualte the molar amount of enzyme per reaction. Then re-express the velocity as mmole/min/mmole = 1/min, convert min to sec and you have the turnover number in 1/s = kat. If you have problems with any of that, ask your instructor to go through the calculation with you. |
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