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#1
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| Dude... there's a universe in all of us. Get a job. |
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#4
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#5
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| On 21 Kwi, 04:29, T-minus108 <foltz...@gmail.com> wrote: I`m sorry. I can't watch futurama in "Enes" Coming back to torus, it*s a very pitty we haven*t any mathematician here. Future belongs to torus ]an from Enes |
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#6
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| "Enes" <[Only registered users see links. ]> and T-minus108 <[Only registered users see links. ]> each wrote something about Dudies, the difference between cosmos and universe, a torus and where zero grawity is, not **** to ****, but very pitty we haven*t any mathematician ]an from "Enes".... hanson wrote: .... ahahaha... listen "Dudies", without you specifying what Zero gravity is... one generally assumes, on the local level, within the reach of human grasp, that zero gravity occurs whenever its influence is cancelled by other forces. OTOH, on the very large, cosmological scale "it is believed", if you believe in the stories/tales that the cosmologists tell you, then there is NO such thing as zero gravity. Every cosmological theory has the following skeleton, a theoretical cosmic envelope, a construct with various additional factors in form of small integers and 1 or more "pi" 's. The equation is kinda pretty when you look at the neat power coefficient decrements of 1,2,3 & 4: c = (G*M/R)^(1/2) = (G*M*H)^(1/3) = (G*M*br)^(1/4) where c = lightspeed, G = Newton; R & M = radius & mass of/in the observable universe, H = Hubble, and br an acceleration from/in any 3D direction that comes out of c^3 = G*M*H & c^4 = G*M*br, hence br = c*H. Running the numbers for it that the astrophysicists have estimated it will show you that br has a value of ~8*E-08 cm/s^2 when using the currently accepted value of M. On/in/or near earth the gravitational acceleration caused by the mass of the earth onto test masses is g ~ 980 cm/s^2. Out there in the averaged intergalactic space br is ~ some 10 billion times smaller the our familiar "g" So, you'll come close to zero gravity but you will never reach zero in the conventional sense as imagined by the cosmological tale(s). Now if you want to twist and tweak your model in order to force br to become zero, then c^4/(GM) must somehow become zero. I let you make the choices and do that. It is more fun that way and I will thank you for the laughs... ahaha... ahahahanson |
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#7
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| On 23 Kwi, 01:39, "hanson" <[Only registered users see links. ]> wrote: .... ehehenes ;[) If influence of gravity is cancelled by other forces -> it is zero summary internal forces. Not zero gravity, I suppose ... I belive in the stories, which have logical and geometrical motivations. So, may be there is zero gravity in the center of all universes. And I do not want to hear ****ing about gravitons without talking about pythagorions... ehehehe ;] [...] At first let somebody return to torus an show us where 0 gravity is, o conditions that : - there is only torus with his mass and the same density, - all other forces are canceled, Future of cosmology rather belongs to toruses ( new kind of BH, protogalaxies, etc.!) |
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#8
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| "Enes" <[Only registered users see links. ]> wrote in message news:[Only registered users see links. ]... Hanson, What is the matter with you ? I am waiting for you answer, that : " No internal, but external forses, but usually internal too"... hanson wrote: .... ahahaha... Enes, I am sorry to tell you that I am here to have fun, to entertain (= ahahaha , "a" for aggravate, and 'h" for heckle) and to be entertained by the likes of you and Einstein Dingleberries. But there are very many posters here who want educate you in their fanaticism... to impress you.. Go for them! Thanks for the laughs, "Dudie"... ahaha.... ahahanson |
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#9
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#10
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| "Enes" <[Only registered users see links. ]> wrote in message news:[Only registered users see links. ]... Enes wrote hanson wrote: I shall do that, Enes. Meanwhile chew on the 1234-equation c = (G*M/R)^(1/2) = (G*M*H)^(1/3) = (G*M*br)^(1/4) which I postend in [Only registered users see links. ] Take care, "Dudie".... ahahaha... ahahahanson |
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