Drop a ball and the surface of the Earth moves up to meet it?

The idea that gravity is equivalent to the ground coming up to meet a
falling object is clear evidence of the failure of Relativity. Only
the ball has gravity acceleration through space or weightless
acceleration.

The station does not accelerate through Earth's space to get closer to
the train. The train comes to the station period. It can be tested by
the clock. The station's clock will run fast or normal because it is
not moving. The train's clock which has accelerated though will run
slow by the Gamma factor of its speed. Compare clocks as the train
passes the station.

Mitch Raemsch Twice Nobel Laureate 2008

greysky wrote:

But, as the train accelerates, it does pull the station (and the earth)
toward it a tiny bit. From the point of view of an observer on the moon,
the earth is accelerated ever so slightly and the station clock slows
down a tiny bit.


--
Paul Hovnanian [Only registered users see links. ]
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Procrastinators: The leaders for tomorrow.

On Apr 1, 8:51*am, "Paul Hovnanian P.E." <[Only registered users see links. ]> wrote:

How do you calculate the tensor for every point on an eliptical curve?

Its a alot of work isn't it?
Infinite calculation to get the whole orbit in fact.

Mitch Raemsch Twice Nobel Laureate 2008

On Mon, 31 Mar 2008 22:31:42 -0700, "greysky" <[Only registered users see links. ]>
wrote:

Unless someone simultaneously drops another ball of the same mass and
elevation, from a point diametrically opposite on the earth.

PD wrote:


Both fall around a common center of gravity.

Bob Kolker

[Only registered users see links. ] wrote:

Calculate every other point and then interpolate. :-)


Well then, get to work. And don't come back until you're done.


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Paul Hovnanian mailto:[Only registered users see links. ]
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