"HVAC" <MR.HVAC@gmail.com> wrote in message

news:1185015826.166092.188800@n60g2000hse.googlegr oups.com...

This is the classic Physics 1/A trick question when they teaching you the

concept of vector units.

In two hours you went nowhere. Zero.

In practice, since for the intents that it is applied, basic physics applies

to a world with 3 dimensions of freedom for movement.

So at any "instant" the speed the first derivative of a function which maps

time elapsed since you started to displacment from where you started. You

could represent this by the length of a straight line or the sum three

vectors, one for each dimension, right?

If you want to know the length of the imaginary lines on the ground you

made, then you need to integrate that entire function, which you are going

to need GPS for. Or if you use the values in the question I'd guess it was

more of an algebra problem, and I don't even like to think about algebra I

use mathematica

I think the answer you are looking for is the fact that average velocity is

the displacement from origin divided by the time of the "jog". Since at the

end you were back where you started, you are dividing the time, which no

matter how long, into zero displacement and everybody knows that zero

divided by anything is still zero - actually it's not a mathematical truth,

it's just a concept to keep math people from going insane. Zero is a

concept, not a quantity.