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Jogging

Jogging - Physics Forum

Jogging - Physics Forum. Discuss and ask physics questions, kinematics and other physics problems.


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  #21  
Old 07-23-2007, 07:37 PM
OG
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"N:dlzc D:aol T:com (dlzc)" <[Only registered users see links. ]> wrote in message
news:sRVoi.32695$[Only registered users see links. ]...

The 'same-time' average of 6 and 12 is indeed 9, but the distance travelled
at each speed is the same, so the 'same-distance' average is 8.





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  #22  
Old 07-24-2007, 12:19 PM
William Wingstedt
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On Tue, 24 Jul 2007 04:12:43 GMT, "Herman Family"
<[Only registered users see links. ] > wrote:


Only if we ignore that while jogging, he was on a planet that is
rotating on its axis, orbiting a star that is revolving around the
central mass of a galaxy. It would also be nice to know how steep the
hill was so we can figure the true horizontal distance. There is no
way the displacement is zero.


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  #23  
Old 07-24-2007, 12:19 PM
William Wingstedt
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On Tue, 24 Jul 2007 04:12:43 GMT, "Herman Family"
<[Only registered users see links. ] > wrote:


Only if we ignore that while jogging, he was on a planet that is
rotating on its axis, orbiting a star that is revolving around the
central mass of a galaxy. It would also be nice to know how steep the
hill was so we can figure the true horizontal distance. There is no
way the displacement is zero.


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  #24  
Old 07-26-2007, 03:34 AM
Dan
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On 7/21/07 10:36 AM, Aaron wrote:

"How far I jogged" does not mean "did my position change, start =? end".
You do work jogging so it makes sense to assign a scalar value to the
distance.
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  #25  
Old 07-26-2007, 03:34 AM
Dan
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Default Jogging

On 7/21/07 10:36 AM, Aaron wrote:

"How far I jogged" does not mean "did my position change, start =? end".
You do work jogging so it makes sense to assign a scalar value to the
distance.
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  #26  
Old 07-26-2007, 03:42 AM
Dan
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On 7/24/07 7:19 AM, William Wingstedt wrote:

I think the frame of reference is assumed to be planet earth. Anyway,
even if that frame is moving, its movement is irrelevant when it comes
to energy expended as long as frame is not accelerating.
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  #27  
Old 07-26-2007, 03:42 AM
Dan
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On 7/24/07 7:19 AM, William Wingstedt wrote:

I think the frame of reference is assumed to be planet earth. Anyway,
even if that frame is moving, its movement is irrelevant when it comes
to energy expended as long as frame is not accelerating.
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  #28  
Old 07-26-2007, 04:11 AM
Dan
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On 7/23/07 2:37 PM, OG wrote:

Just look at distance up hill, B, and assume it is 10 meters. Since
D=V*T, 10=6T1 and 10=12T2. So average speed is V = 20 / (10/6 + 10/12)
= 20 / (30/12) = 240 /30 = 8.
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  #29  
Old 07-26-2007, 04:11 AM
Dan
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Default Jogging

On 7/23/07 2:37 PM, OG wrote:

Just look at distance up hill, B, and assume it is 10 meters. Since
D=V*T, 10=6T1 and 10=12T2. So average speed is V = 20 / (10/6 + 10/12)
= 20 / (30/12) = 240 /30 = 8.
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  #30  
Old 07-26-2007, 09:29 PM
bob
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On Wed, 25 Jul 2007 23:11:43 -0500, Dan <[Only registered users see links. ]> wrote:


Exactly!
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