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Jogging

Jogging - Physics Forum

Jogging - Physics Forum. Discuss and ask physics questions, kinematics and other physics problems.


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  #11  
Old 07-22-2007, 12:53 AM
OG
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"Rich Corinthian Leather" <[Only registered users see links. ]> wrote in message
news:Cuxoi.3447$[Only registered users see links. ].prodigy.ne t...

And apart from being a comprehensive answer the only problem is that it's
wrong.

You know from the text that he ran the same DISTANCE uphill as downhill, but
your calculation implies that he spent the same TIME doing both. Your
calculation implies that the hill was twice as long going down as going up.

My guess is that you're either a
alien research kinda guy
or a paranormal kinda guy
or a crop-circle kinda guy

I'll be happy to continue discussions with atheists and alt.physicists


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  #12  
Old 07-22-2007, 10:52 PM
andy everett
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HVAC wrote:

velocity*time = distance

VT=D --> T = D/V = 2*A/8 + B/6 + B/12 = 2hours and A is the flat
distance and B is the hill distance.

We have one equation with two unknowns, we are stuck.
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  #13  
Old 07-22-2007, 10:52 PM
andy everett
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HVAC wrote:

velocity*time = distance

VT=D --> T = D/V = 2*A/8 + B/6 + B/12 = 2hours and A is the flat
distance and B is the hill distance.

We have one equation with two unknowns, we are stuck.
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  #14  
Old 07-23-2007, 12:56 AM
bob
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On Sun, 22 Jul 2007 22:52:14 GMT, wrote:


Wrong. The answer is 16 miles because the average speed of the runner
is 8 miles per hour whether for any value of A and B. This hint should
be way more than enough.
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  #15  
Old 07-23-2007, 12:56 AM
bob
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On Sun, 22 Jul 2007 22:52:14 GMT, wrote:


Wrong. The answer is 16 miles because the average speed of the runner
is 8 miles per hour whether for any value of A and B. This hint should
be way more than enough.
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  #16  
Old 07-23-2007, 04:08 AM
N:dlzc D:aol T:com \(dlzc\)
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Dear bob:

"bob" <[Only registered users see links. ]> wrote in message
news:[Only registered users see links. ]...
....

The average of 6 and 12 is 9.


I think the "Maliatzzi brothers" ("Car Talk" on NPR) got it wrong
too.

David A. Smith


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  #17  
Old 07-23-2007, 04:08 AM
N:dlzc D:aol T:com \(dlzc\)
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Dear bob:

"bob" <[Only registered users see links. ]> wrote in message
news:[Only registered users see links. ]...
....

The average of 6 and 12 is 9.


I think the "Maliatzzi brothers" ("Car Talk" on NPR) got it wrong
too.

David A. Smith


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  #18  
Old 07-23-2007, 10:15 AM
andy everett
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bob wrote:

T = 2*A/8 + 2*B/12 + B/12 = 2*A/8 + 2*B/8 = (A+B)/8 = 2hours

8 * 2hours = (A+B) = 16 miles



Right, %^)
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  #19  
Old 07-23-2007, 10:15 AM
andy everett
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Default Jogging

bob wrote:

T = 2*A/8 + 2*B/12 + B/12 = 2*A/8 + 2*B/8 = (A+B)/8 = 2hours

8 * 2hours = (A+B) = 16 miles



Right, %^)
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  #20  
Old 07-23-2007, 07:37 PM
OG
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"N:dlzc D:aol T:com (dlzc)" <[Only registered users see links. ]> wrote in message
news:sRVoi.32695$[Only registered users see links. ]...

The 'same-time' average of 6 and 12 is indeed 9, but the distance travelled
at each speed is the same, so the 'same-distance' average is 8.





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