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#1
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| Sorry if this is the incorrect place to post this question. If you have something like a motor turning a shaft at 60 revolutions per min, how would you figure out what kind of system of gears you would need to either increase the RPM's by a factor of 2, 5 and 10. And what kind to decrease the RPM's by the same. I'm would think you could use a myriad variety of gears but I'm looking for the most simple. That is a system that would double the RPM's. A system that would half the RPM's. A system that would increase the RPM's 5 times. A system that would increase the RPM's 10 times. A system that would decrease the RPM's 5 times. ....ect. I'm sure it is a basic way to do one and from that I could probably figure out the rest. If you can help me, I'd be most grateful. eVe |
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#2
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| Dear eVe GiiDiiOn: eVe GiiDiiOn wrote: Known: output ratio Given: gear drive Formula: output ratio = nt_i / nt_o with nt_i = number of teeth on input gear with nt_o = number of teeth on output gear You just need to make sure the two gears have the same pitch, etc. [Only registered users see links. ] You can also do this job with a pair of pulleys and belt. You can also do this job with a variable speed motor. You might ask future questions of this type on sci.engr.mech. David A. Smith |
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