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#1
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| Dear Reader, First of all let me thank you for taking interest in lending a helping hand for my issue. The issue is that i ve to design one autotransformer with secondary tapped from the primary and is kept at a voltage equal to 106V. The primary has 7 taps ranging from 0 Volts to 187V in steps of 110% of rated voltage which is 110V. so the taps will be 121,132,143,154,165,176 and 187V tap. the load on the secondary will be around 2.1K. i ve used the formula V2/V1=N2/N1=I1/I2, Where V-Voltage, N-No of turns, I-Current. The secondary load current is 43mA. N2 is currently 3600 which is fixed. Since V2 is needed to be 106V, V1 is 121V for first tap. so from the above expression I1 can be found, and then N1 can be found. this is repeated for remaining taps. This is how i ve done the designing. Is this OK or any other method has to be adopted. Please help me. Thanking You Regards Pavan |
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#2
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#3
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| Dr. Video, How ever You want you can take it but there is really an importance behind me asking this question. Rather frankly it has an end use. i am working on this. Regards Pavan Dr.Video wrote: |
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#4
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| I am unclear on whether or not you're actually buiding one from scratch or are utilizing an existing one. If you simply need to step down from 121 to 106 VAC, you can do this with a number of off the shelf transfomers that have a 120v pri & a 12-15 v sec. Simply wire the sec to buck the pri, you create an autotransformer that will step down to your specs. "pavan" <[Only registered users see links. ]> wrote in message news:1161758840.404985.185330@i3g2000cwc.googlegro ups.com... be |
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| autotransformer , design |
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