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#11
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| PD wrote in message <1135691117.934683.47610@o13g2000cwo.googlegroups. com>... Substitute time for J, and amps/t for current. After algebraic manipulation of the time variable t, the dimension problem has gone away. charge opposite down up direct the an correctly current imaginary imaginary time inconsistency. the a which qualifies __________________________________________________ __________________________ ___ [Only registered users see links. ] <><><><><><><><> __________________________________________________ _____________________________ Posted Via Uncensored-News.Com - Accounts Starting At $6.95 - [Only registered users see links. ] <><><><><><><> The Worlds Uncensored News Source <><><><><><><><> |
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#12
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| It's been done already. i was even surprised to learn (from Jim Black) that lightyears = (i) * years Or, to use your notation, lightyears = ( 0 + i ) * years Apparently - this is all standard relativity, almost 100 years old now, or should I say that it's almost 1 / (100i) lightyears ago (?) |
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#13
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| JESUS. 100 years = 100 / ( 0 + i ) lightyears. SOMEBODY SPLAP ME. |
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#14
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| In sci.physics, [Only registered users see links. ] <[Only registered users see links. ]> wrote on 4 Feb 2006 19:43:56 -0800 <1139111036.801323.189110@g47g2000cwa.googlegroups .com>: Well, here's a thought. The standard Minkowski metric is x^2 + y^2 + z^2 - c^2t^2 so perhaps your formula is better expressed 100 years = 100 / (ic) lightyears where c is 1 lightyear per year. If one prefers slightly more manageable units, 100 seconds = 100 / (ic) meters where c is 299792458 m/s. -- #191, [Only registered users see links. ] It's still legal to go .sigless. |
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#15
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#16
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| stone wrote: Subsituting one quantity for another and noticing that the algebra is still ok does not indicate that what results has any bearing on reality. PD |
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| imaginary , number , time |
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