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#1
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| I have a function, f(x, y)), integrated over an area defined as a quarter circle in quadrant 1. That is, an area defined between 0 and 90 degrees with a radius of 1. I can define this result in Cartesian coordinates as (using "S" as the integral sign): (1) SS f(x, y) dx dy or, in polar coordinates as, (2) SS f(r) r dr dT where dT is shorthand for d(Theta). I can make the conversion from Cartesian to polar using the transformations of (3) x = r cos(T) and (4) y = sin(T). dx and dy just fall out of those relationships. My question comes thus. Can I simply treat dx and dy as any other variable, multiply, simplify them and do the integration? I would have said yes. However, in a real example where, (5) f(x, y) = square root (1 - x2 - y2) = f(r) = square root (1 - r2) I did a numerical integration. I get the expected answer, pi / 6, by doing (1) or (2). But, if I expand (1) using (3) and (4) the numerical integration does not work. Any thoughts? Best regards, Thomas |
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#2
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| Sorry for the potentially confusing typo, (4) below should be y = r sin(T) Thomas Thomas wrote: |
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| integration , numerical , variables |
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