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What's the rule about using 'ones' in algebra?

What's the rule about using 'ones' in algebra? - Physics Forum

What's the rule about using 'ones' in algebra? - Physics Forum. Discuss and ask physics questions, kinematics and other physics problems.


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  #11  
Old 09-22-2003, 02:09 PM
Bill Vajk
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Default What's the rule about using 'ones' in algebra?

Donald G. Shead wrote:






You are too kind.



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  #12  
Old 09-22-2003, 05:23 PM
Martin Hogbin
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Default What's the rule about using 'ones' in algebra?


"Donald G. Shead" <[Only registered users see links. ]> wrote in message news:jqtbb.7153$[Only registered users see links. ].prodigy.com ...

Very fetching Don. You are now reaping the rewards of being
a persistent and wilfully ignorant spammer.

Martin Hogbin


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  #13  
Old 09-22-2003, 08:25 PM
Donald G. Shead
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Default What's the rule about using 'ones' in algebra?


"Martin Hogbin" <[Only registered users see links. ]> wrote in message
news:bknb79$ds3$[Only registered users see links. ]...
news:jqtbb.7153$[Only registered users see links. ].prodigy.com ...
What
can't
it.
rule;
Here I go again Martin(:-) _You_ are perhaps one of the goofiest goofoffs
yet: By wasting internet "bandwidth" improperly; just to get your digs in.

There appears to be _no_ redeeming value here whatsoever: Either for your
cause or mine. Don't you have any opinion, or have anything to say about the
_subject_?

I'm thinking that with the consistent (fps) units of the foot-pound-second
system of weights and measures: Acceleration [a] is not inversely
proportional to 1/m; but [a] _is_ proportional to f/m!

Therefore [f] is not _equal_ to [ma]! A body's mass [m] is proportional to
the ratio of the (net) force [f], divided by the acceleration [a] that
occurs; due to that force: Therefore f/a = 1# secē/foot = w/g = 5.33#
secē/5.33 feet =32# secē/32 feet....

So since mass [m] is proportional to the ratios: m = f/a = w/g:

f = (w/g)a [= (f/a)a]
w = (f/a)g [=(w/g)g]

Any pros or cons are welcome Martin(:-|


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