equal loading proteins and lowry assay

[fourthdragon]

I have a question about the lowry assay and equal loading proteins for electrophoresis. My advisor wants me to equally load 20ug of proteins from 25ul in a gel. I have the protein concentration from the lowry assay. What is the equation that you use to figure out what protein volume should be loaded from the sample. The equation that he gave me doesn't seem right. Any help with this problem would be appreciated.

[protolder]

Hola, from the lowry assay you have concentrations in mg/ml, haven´t you? well the transformation is easy. suppose that your sample is 2mg/ml<>2ug/ul so to have 20ug =>20/2= 10ul to load; if you want to have them in 25ul add 15 ul of buffer. the same for other concentrations. Under .8 mg/ml you have the limit of volume20/.8=25 ul of sample to load. If you have 0.5mg/ml; 20/0.5 40ul to load. Buena suerte

[protolder]

continue.- So you have divide 20 by your concentration and add the buffer volume to get 25 ul. One more thing lowry has been changed in the labs by Bradford, easier and faster. Buena suerte