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#1
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| So I have the two spectra for these molecules. They are fairly the same except for the peak of m/z 121, which is a m-15 peak...meaning it loses a methyl group...or at least that is my assumption. What I don't understand is why it is a strong peak for 2-carene and a weak peak for 3-carene. Any advice would be appreciated! |
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#2
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| Quote:
3,7,7-Trimethylbicyclo[4.1.0]hept-2-ene -- 3-carene 3,7,7-Trimethylbicyclo[4.1.0]hept-3-ene 1. check lot no's - synthetic routes may differ 2. check reagent stability of 2 -vs- 3-carene 3. assume the m=15 is something other than CH3 4. assume the position of the double-bond is significant 5. perform an accurate net-sum comparison of peaks 6. perform instrument maintenance and test for bias |
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#3
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| Well I tried the Reverse-Diels Adler mechanism on the two...and it doesn't work for the 2-carene...is that what you mean by assumnig the position of the double-bond is significant? I am not sure what that tells you about the 121 peak . The m-15 peak has to be a methyl group loss...unless you lose 15 H's?? |
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| 2carene , 3carene |
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