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stechiomeria ;/

stechiomeria ;/ - Forum Chemia

stechiomeria ;/ - Forum Chemia


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Old 10-21-2011, 08:33 AM
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Default stechiomeria ;/



prosze o pomoc w tych zadaniach :

Ile gramów 30.0% roztworu KOH potrzeba, by zobojętnić 121 g roztworu H2SO4, w którym ułamek molowy kwasu Nk = 0.425?
MH2O = 18,02 g/mol MH2SO4 = 98,08 g/mol MKOH = 56,11 g/mol

Do roztworu wodnego NaOH, w którym ułamek molowy NaOH wynosi 0.121, i który zawiera 31.6 moli wody dodano 585 g 60.8 % roztworu wodnego kwasu azotowego(V) o gęstości 1.2653 g/cm3. Jaką wartość ma ułamek molowy NaNO3 w tak otrzymanym roztworze?

z góry dziekuje
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