A chemistry problem dealing with specific heat... From the SAT Chem Review book?

[dpet119]

The specific heat of a substance is approximately 0.5 cal/g-°C. If 30 calories of heat are absorbed by 15 g of the substance at 30°C, it's temperature will become...

ok so i don't even know what to solve for: I'm guessing that:
Specific Heat=.5
Cal.=30
grams=15
DELTA=x
but what about the other variable? Please help

[skipper]

30 calories = 0.5 cal/g C x 15 g x delta T
delta T = 4
final temp = 30 + 4 = 34 deg C

[Shorty]

30cal = 15g X 0.5 cal/ g°C X Delta

30 cal = 7.5cal/ °C X Delta

4°C= Delta

so basically the temp. will become 4°C