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#1
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| NIST ([Only registered users see links. ]), which I tend to believe, gives -2,214.31 kJ/mol for P4O6 vapour's delta 'H'. Halfway down [Only registered users see links. ], however, is a diagram ([Only registered users see links. ]) that shows it as -1,318 kJ/mol for the solid. And some sources say it decomposes. In air, sure, it would decompose to P4O10, but I don't understand how it could decompose all on its own. This sort of discordancy might make sense for, um, aluminum bismuthide but phosphorus (III) oxide doesn't seem that obscure. Please shed some light. --- Graham Cowan [Only registered users see links. ] -- fireproof fuel, real-car range, no emissions |
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#2
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| G. R. L. Cowan wrote: Looks as if the NIST data is based on reacting P4 vapor, the other on solid P4. Decomposition could be disproportionation to phosphorous and P4O10. Rob. |
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#3
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#4
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| Jaak Suurpere wrote: Since posting I've thought, maybe the low-magnitude figures actually pertain to mixtures of P4 and P4O6, such as would be easy to get if one tried to make P4O6 by burning P4 with limited oxygen. P4 melts 44.1 C, boils 280 C. P4O6 melts 23.8 C, boils 175.4 C. If NIST is right, it won't disproportionate -- P4O6(g) ---> (2/5) P4(g) + (3/5) P4O10(s) -2214.31 47.1 -1805.964 but if the -1,318-kJ/mol figure is right, it should disproportionate like crazy, and why would phosphorus combustion ever produce it. --- Graham Cowan [Only registered users see links. ] -- fireproof fuel, real-car range, no emissions |
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#5
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| [Only registered users see links. ] wrote: So NIST's 900 more reported kJ/mol is how far P4(g) is above P4(s)? It boils at 280 C. As noted in my other posting, disprop won't happen if NIST is right, otherwise maybe, But if some work had been done on P4O6 that bore a large adulteration of P4 -- both colourless, nearly the same mp and bp -- and other, more careful work had used pure P4O6, all this would be explained. --- Graham Cowan [Only registered users see links. ] -- fireproof fuel, real-car range, no emissions |
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#6
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| G. R. L. Cowan wrote: My trusty Atkins gives the following data for standard enthalpies of formation for phosphorus species (KJ/mol): P (wh, s) 0 (duh) P(g) + 314.64 P2(g) + 144.3 P4(g) + 58.91 P4O10(s) -2984.0 P4O6(s) -1640.1 Note that these are enthalpies, not free energies of formation, but disprop to P4 and P4O10 would be exothermic on that data. 5P4O6 --> 2P4 + 3P4O10 /\H = -752kJ/mol. Maybe NIST confused data for P4O10 with P4O6? - It's in the right ballpark for gaseous pentoxide. A trip to the nearest Rubber Book might help. Rob. |
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#7
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| [Only registered users see links. ] wrote: Your rubber book has entries for P4On? Or even "P2On"? NIST has entries for both P4O6 (gas phase only, delta 'H' of f -2.2 MJ/mol) and P4O10 (both gas and solid phase, enthalpies in MJ/mol respectively -2.9, -3.0). --- Graham Cowan [Only registered users see links. ] -- "Boron: A Better Energy Carrier than Hydrogen?" |
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| 315 , 529 , dhf , fragile , kcal or mol , p4o6g |
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