Interview Question - Too Tough?

The following interview question (or something similar) will be aimed at a
recent graduate ... is this too tough?

The following reaction is depicted in SMILES strings. Please name: the
starting material, product and reaction type. The reaction of
O=C(OC)CCC(OC)=O and O=CC1=CC=CC=C1 in the presence of a strong base and
suitable solvent gives OC(CC(C(OC)=O)=CC1=CC=CC=C1)=O.

Darren.

In article <<bo5uhi$36h$1@hercules.btinternet.com>,> Darren Rhodes
(darren.rhodes5@btopenworld.com) says...

I'm not sure recent graduates will know what SMILES strings are (well,
I didn't know what they really were until a year or so into my
attempted Ph.D., anyway), but if you mean the structures represented
by those strings then I guess it might be OK - the name of the product
*might* be a bit testing . BTW, why don't you get
OC(/C(CC(OC)=O)=C\C1=CC=CC=C1)=O (if you're having difficulties
translating it back, let me know and I'll stick a picture up on some
webspace) instead or as a by-product? (Or is that a follow-up
question )

Stephan
--
Stephan Bird MChem(Hons) AMRSC
Currently in Oxford, England

[sajimar25]

Yes, that is too tough!

[MicroBioKing]

Lots of times in interviews they are not looking for the right answer (although that will never hurt) but they're looking to see how you think, or how you go about solving a hard problem.

[maccolliens]

When you go for interview that time prepared very well all the formula and mixer of organic chemistry and give answer very carefully.

[aion12]

I am newbie, to learn. Hope that we can take care

[hua052011]

Hi

I found that a member asked same question in this forum some months ago.

Pls use search box to find this questions with comments

[aymanbinmoshi]

Originally Posted by Darren Rhodes

The following interview question (or something similar) will be aimed at a
recent graduate ... is this too tough?

The following reaction is depicted in SMILES strings. Please name: the
starting material, product and reaction type. The reaction of
O=C(OC)CCC(OC)=O and O=CC1=CC=CC=C1 in the presence of a strong base and
suitable solvent gives OC(CC(C(OC)=O)=CC1=CC=CC=C1)=O.

Darren.

Let me just 2 day. I will come with the answer. I am sure that I will find the answer. Most possibly I knew it but....

[thu062012]

Hi,

Thanks very much for this comment. It help me to think about my ideals.

Tks again and pls keep posting.

[brettjohnson]

The following interview question :

1. What is range of PH ?

2.Different between ACID and BASE ?

3.Any 2-3 example of strong acid , Base , Acid ?