- **BioStatistics Forum**
(*http://www.molecularstation.com/forum/biostatistics-forum/*)

- - **Statistical help required urgently**
(*http://www.molecularstation.com/forum/biostatistics-forum/3550-statistical-help-required-urgently.html*)

Statistical help required urgentlyHi all, I have two absolute quantitation assays that I use to generate a readout of copies of target per pg of input RNA. Both assays generate a standard deviation (each sample is done in triplicate), one in copies per reaction (target assay) and one in pg of RNA per reaction (endogenous assay). Is there a method of combining the two standard deviations to get an overall error value for the assay? They are different units, so I am uncertain if this is even possible. If it cannot be done this way, is there a statistical conversion I can do to demonstrate any kind of standard error/deviation? Thanks, Iain. |

Re: Statistical help required urgentlyI think you want CV. see ---> [Only registered and activated users can see links. Click Here To Register...]I does not combine your two std deviations, instead you will pick one and turn it into percent of the mean. This makes it more readable to say 55ng + or - 10% instead of 55ng + or - 5.5ng. |

Re: Statistical help required urgentlyHi danfive, thanks for your reply. I am still a bit unsure of this though. Can i use the mean square error of the two cvs to get an overall standard error for the assay. As an example, Sample 1 contains 1e6+/-2e4 copies per reaction of my viral target Sample 2 contains 1e5+/-3e3 pg of total RNA (GAPDH endogenous QPCR) I would represent this as 10 copies of target per pg of RNA Using CV: The CV for the target assay is (2e4/1e6)*100 = 2% The CV for the endogenous assay is (3e3/1e5)*100 = 3% Can I calculate a mean square error using the formula? mse = sqrt((cv1*cv1)+(cv2*cv2)) = sqrt(4+9) = 3.0655% Therefore my result would be 10 copies per pg of total RNA +/- 3.07% Is this a valid use of mean square error? Any and all help gratefully received. Thanks, Iain. |

Re: Statistical help required urgentlyIf I have this right: Assay 1: Tells you absolute copy number of Target gene Assay 2: Tells you pg RNA of GAPDH gene If so you want to use target gene to reference gene normalization. This may help, read sections for absolute quantification and normalization of expression ---> [Only registered and activated users can see links. Click Here To Register...]You may also want to look into this reference on the issue of error bars in experimental biology ---> [Only registered and activated users can see links. Click Here To Register...] |

All times are GMT. The time now is 08:19 PM. |

Powered by vBulletin® Version 3.8.4

Copyright ©2000 - 2014, Jelsoft Enterprises Ltd.

Copyright 2005 - 2012 Molecular Station | All Rights Reserved